A circle is touching the side BCBCBC of △ABC△ABC△ABC at PPP and touching ABABAB and ACACAC produced at QQQ and RRR respectively. Prove that AQ=12(Perimeter of △ABC)AQ=12(Perimeter of △ABC)AQ=12(Perimeter of △ABC).
Answer:
- We know that the lengths of tangents drawn from an external point to a circle are equal.
Thus, [Math Processing Error] - We know that the perimeter of a triangle is the sum of the lengths of its sides. [Math Processing Error]
- Therefore, AQ=12(Perimeter of △ABC).AQ=12(Perimeter of △ABC).