A triangle ^@ABC^@ with ^@\angle ABC = 90^\circ^@, has the lengt | Math Question and Answer

Answer:

$76.8 \space cm$

Step by Step Explanation:

In the right angled triangle $ABC, AB = 128 \space cm, BC = 96 \space cm$
$\begin {align} Now, \space AC & = \sqrt{ (AB)^2 + (BC)^2 } && \ldots \text { (As per Pythagoras Theorem) } \\ & = \sqrt{(128)^2 + (96)^2} \\ & = \sqrt{(16384 + 9216)} \\ & = \sqrt{(25600)} \\ & = 160 \space cm \end {align}$
$\begin {align} \text { The area of the right angled triangle ABC, when base is } BC & = \dfrac { AB \times BC} {2} \\ & = \dfrac { 128 \times 96 } {2} \\ & = 6144 \space cm^2 && \ldots(1) \end {align}$
$\begin {align} \text { The area of the right angled triangle ABC, when base is AC } & = \dfrac { AC \times BD } {2} \\ & = \dfrac { 160 \times BD } {2} && \ldots(2) \end {align}$
Since, the area in the equations $(1)$ and $(2)$ should be the same, equating the area in equation $(2)$ , we get:
$\begin {align} & \implies \dfrac { 160 \times BD } {2} = 6144 \\ & \implies 160 \times BD = 12288 \\ & \implies BD = \dfrac { 12288 } { 160 } \\ & \implies BD = 76.8 \space cm \end {align}$
Therefore, the length of the perpendicular line from side $AC$ to point $B$ is $76.8 \space cm$ .

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