Construct a right triangle whose base is 17 cm and sum of its hypotenuse and another side is 23 cm.
Answer:
Let ABC be the required triangle such that BC=17 cm,∠B=90∘ and AC+AB=23 cm. Draw a BC=17 cm. At B construct ∠CBX=90∘. From B cut off BD=23 cm. Join CD and draw perpendicular bisector of CD intersecting BD at A. Join AC to get the required triangle ABC.