Construct a right triangle whose base is 17 cm and sum of its hypotenuse and another side is 23 cm.


Answer:

C B X D A

Step by Step Explanation:
  1. Let ABC be the required triangle such that BC=17 cm,B=90 and AC+AB=23 cm. Draw a BC=17 cm. C B
  2. At B construct CBX=90. C B X
  3. From B cut off BD=23 cm. C B X D
  4. Join CD and draw perpendicular bisector of CD intersecting BD at A. C B X D A
  5. Join AC to get the required triangle ABC. C B X D A

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